Результаты поиска по запросу: P7P4Q
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a) White Mates in 4. Vidmar vs Augustin Neumann, Vienna, 1903 r3k2N/1b1pn2p/2qB1bp1/p7/p4Q2/2N5/PPP2PPP/4R1K1 w - - 0 1 [ Rxe7+ if Bxe7 Qf7+ or if Kd8 Nf7+ ].
www.wtharvey.com/vidm.html
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p7? p4? q5?
laserpointerforums.com/f57/p7-led-43339.html
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Example 2: Use factoring by grouping to factor 7p2 - 4pq + 12 q4 - 21pq3.
www.mathcaptain.com/algebra/distributive-property.html
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9l 5lg 9s 5l0 9t 5ks 9u 5l4 a7 5lh a4,5lh a6 5lh ac 5lh ag 5ls ab 5ls 9v 5m1 a1 5mf a1 5ma 9o 5lp 9k,5lo 9j. 5lk 9e 5li 9h,km 6s pd 6t#42 1i 5k 0 5k 26,-2g 0 5k 0,5k 35 5k 2u,32 7u 23 7s 24 8k 2s 8k,3p 7j 3o 8h 4g 8f 4d.
armorgames.com/user/eduh/2
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E �R8�m �cs� |.Ԁυ ~���7��5�� ,XⅡ�%�ص�� G��u �4��[�Z����� x8]S�Sl[Y+ �4 �� ep4��Q^�@qN ��P` �� | d�Dz,��Pj���Xg�hG� ��n! � �K\�� ~���c �{�XM/V�k�����߈��e��-�x]����]����3P�� *7 � p4 ��Q.G � ވ��. ... � p<�� � � p<�� � � p<�� � � p<�� ��F u� �Y�� � �x�� � �x�� � �x�� � �x�� ���8...
www.ti.com/lit/ds/symlink/ds92lv3221.pdf
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The expected utility that individual i derives from choosing major m at time t is: 4 Uimt (b; d; Xit ; fPimt (br = 1)g7 r =1 ; fEimt (dq )gq =1 ) = (5) P4 q =1 iqt Eimt (dq ) = Equation (4) can now be written as: P7 r=1 Pimt (br = 1)4ur (Xit ) + P7 r =1 ur (br = 0
www.newyorkfed.org/research/staff_reports/sr364.pdf
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127] = "rnb1kb1r/ppp2ppp/3p4/1q1N4/4PQn1/8/PPP2PPP/R1B1K1NR"; glb_forsythe_str[128] = "rnb1kb1r/ppN2ppp/3p4/1q6/4PQn1/8/PPP2PPP/R1B1K1NR"
www.logicalchess.com/hcc/puzzles/bestmove1.html
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www.freerider2game.com/play-track/154218/
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Primary (citable) accession number: Q15181 Secondary accession number(s): Q2M348 , Q5SQT7, Q6P7P4, Q9UQJ5, Q9Y5B1. Entry history. Integrated into UniProtKB/Swiss-Prot
www.uniprot.org/uniprot/Q15181
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8/5ppk/5b1p/3p3P/3NP3/P1P2P2/P5q1/KR2R3 b - - bm Bxd4; c0 "<Houdini 1.5a w32> score cp -8"; 8/5ppk/7p/7P/3PR3/P7/P4q2/K3R3.
www.fam-petzke.de/downloads/TD-SUB-2000.epd
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